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Sagot :
Answer:
x=0
Step-by-step explanation:
[tex]3x(3x-1)-(3x+5)(3x-5)=3x+25\\\\\text{Use the algebraic identity,}(a+b)(a-b)=a^2-b^2\\9x^2-3x-(9x^2-25)=3x+25\\9x^2-3x-9x^2+25=3x+25\\-3x=3x\\-6x=0\\x=0[/tex]
Answer:
[tex]\sf x=0[/tex]
Step-by-step explanation:
[tex]\sf 3x\left(3x-1\right)-\left(3x+5\right)\left(3x-5\right)=3x+25[/tex]
[tex]\sf -3x+25=3x+25[/tex]
[tex]\sf -3x+25-25=3x+25-25[/tex]
[tex]\sf -3x=3x[/tex]
[tex]\sf -3x-3x=3x-3x[/tex]
[tex]\sf -6x=0[/tex]
[tex]\sf \frac{-6x}{-6}=\frac{0}{-6}[/tex]
[tex]\sf x=0[/tex]
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