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Answer:
[tex]z=k-\frac{8T}{9} -\frac{a}{9}[/tex]
Step-by-step explanation:
[tex]9k-8T=9z+a\\9k-8T-a = 9z\\\frac{9k-8T-a }{9}= \frac{9z}{9} \\k-\frac{8T}{9} -\frac{a}{9} = z\\z=k-\frac{8T}{9} -\frac{a}{9}[/tex]