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Sagot :
The ball will decelerate as it moves upwards.
The magnitude of the ball's acceleration is 0.3 m/s² and it directed backwards.
The given parameters;
- initial velocity of the ball, u = 1.25 m/s
- time of motion of the ball, t = 4.22 s
As the ball rolls up the inclined plane, the velocity decreases and eventually becomes zero when the ball reaches the highest point of the plane.
Thus, the ball decelerate as it moves upwards.
The acceleration of the ball is calculate as;
[tex]a = \frac{v_f -v_0}{t} \\\\[/tex]
at the highest point on the incline plane, the final velocity [tex]v_f[/tex] is zero
[tex]a = \frac{0-1.25}{4.22} \\\\a = -0.3 \ m/s^2[/tex]
Thus, the magnitude of the ball's acceleration is 0.3 m/s² and it directed backwards.
Learn more here:https://brainly.com/question/23860763
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