Join the growing community of curious minds on IDNLearn.com. Receive prompt and accurate responses to your questions from our community of knowledgeable professionals ready to assist you at any time.
Sagot :
The ball will decelerate as it moves upwards.
The magnitude of the ball's acceleration is 0.3 m/s² and it directed backwards.
The given parameters;
- initial velocity of the ball, u = 1.25 m/s
- time of motion of the ball, t = 4.22 s
As the ball rolls up the inclined plane, the velocity decreases and eventually becomes zero when the ball reaches the highest point of the plane.
Thus, the ball decelerate as it moves upwards.
The acceleration of the ball is calculate as;
[tex]a = \frac{v_f -v_0}{t} \\\\[/tex]
at the highest point on the incline plane, the final velocity [tex]v_f[/tex] is zero
[tex]a = \frac{0-1.25}{4.22} \\\\a = -0.3 \ m/s^2[/tex]
Thus, the magnitude of the ball's acceleration is 0.3 m/s² and it directed backwards.
Learn more here:https://brainly.com/question/23860763
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Discover insightful answers at IDNLearn.com. We appreciate your visit and look forward to assisting you again.