[tex]\huge\text{Hey there!}[/tex]
[tex]\large\textsf{5(1 + 4h) + 2h = 27}\\\large\textsf{5(1) + 5(4h) + 2h = 27}\\\large\textsf{5 + 20h + 2h = 27}\\\large\large\textsf{5 + 22h = 27}\\\large\textsf{22h + 5 = 27}\\\large\text{SUBTRACT 5 to BOTH SIDES}\\\large\textsf{22h + 5 - 5 = 27 - 5}\\\large\text{CANCEL out: 5 - 5 because that gives you 0}\\\large\text{KEEP: 27 - 5 because that helps us solve for the h-value.}\\\large\textsf{27 - 5 = \bf 22}\\\large\text{DIVIDE 22 to BOTH SIDES}\\\mathsf{\dfrac{22h}{22} = \dfrac{22}{22}}[/tex]
[tex]\\\large\text{CANCEL out: }\rm{\dfrac{22}{22}}\large\text{ (the one on the LEFT) because it gives you 1}\\\large\text{KEEP: }\rm{\dfrac{22}{22}}\large\text{ (the one on the RIGHT) because it gives you the result of the h-value}\\\large\text{SIMPLIFY ABOVE AND YOU HAVE YOUR ANSWER OF H}\\\\\\\huge\boxed{\rm{Therefore, \ h = 1}}\huge\checkmark[/tex]
[tex]\large\textsf{Therefore, Ahmad is incorrect with his steps because he didnt}\\\large\textsf{5 within the parentheses and didnt combine the like terms for the}\\\large\textsf{2}\mathsf{^{nd}}\large\textsf{ step. }[/tex]
[tex]\large\text{Good luck on your assignment and enjoy your day!}\\\\\\\frak{Amphitrite1040:)}[/tex]
