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mathematics Areas and perimeters ​

Mathematics Areas And Perimeters class=

Sagot :

Answer:

54.5 Sq. cm

Step-by-step explanation:

area of a right angled triangle = 1/ 2 × base × height

(here, the base is 8 and height is 6)

= 1/ 2 × 6 × 8

= 4 × 6

= 24 Sq. cm

area of a circle = [tex] \pi [/tex] r²

(r is the radius that is diameter/ 2, and the value of [tex] \pi [/tex] is 3. 14)

  • r = 10/ 2 = 5 cm

= 3. 14.× (5)²

= 3.14 × 25

= 78.5 Sq. cm

area of the shaded region = area of Circle - area of triangle

= 78.5 - 24

= 54.5 Sq. cm

that is option 3

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