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x²+x-6=0

hãy tìm giá trị của x trong câu trên

Sagot :

DᴀʀᴋPᴀʀᴀᴅᴏxidn

Tìm giá trị của x :

  • [tex] {x}^{2} + x - 6 = 0[/tex]

  • [tex]x {}^{2} + 3x - 2x - 6 = 0[/tex]

  • [tex]x(x + 3) - 2(x + 3) = 0[/tex]

  • [tex](x + 3)(x - 2) = 0[/tex]

Bây giờ, có hai trường hợp :

Trường hợp 1. khi nào x + 3 = 0

  • x = -3

Trường hợp 2. khi nào x - 2 = 0

  • x = 2

Tôi hy vọng nó đã giúp !

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