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Sagot :
The sum of the first 10 terms of the sequence 4, -12, 36, -144 is -59058
The given geometric sequence is:
4, -12, 36, -144
The first term, a = 4
The common ratio,
[tex]r = \frac{-12}{4}\\r = -3[/tex]
Since we are looking for the sum of the first 10 terms
The number of terms, n = 10
The sum of the first n terms of a geometric sequence is given as:
[tex]S_n = \frac{a(1-r^n)}{1-r} \\S_n = \frac{4(1-(-3)^{10}}{1-(-3)} \\S_n = \frac{4(1-59049)}{4} \\S_n = -59048[/tex]
The sum of the first 10 terms of the sequence 4, -12, 36, -144 is -59058
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