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The point-slope form of the equation of a line that passes through points (8, 4) and (0, 2) is y - 4 = 1/4(x -8). What is
the slope-intercept form of the equation for this line?

Sagot :

Akposevictoridn

The slope-intercept form of the equation of the line that passes through (8, 4) and (0, 2) is: [tex]y = \frac{1}{4}x + 2[/tex]

Recall:

  • You can expressed the equation of a line in slope-intercept form as y = mx + b.
  • slope = m
  • y-intercept = b
  • Equation in point-slope form can be rewritten and expressed as y = mx + b

Given, [tex]y - 4 = \frac{1}{4}(x -8)[/tex]

Rewrite in the form of y = mx + b

  • Thus:

[tex]y - 4 = \frac{1}{4}x - 2[/tex]

  • Add 4 to both sides

[tex]y - 4 + 4 = \frac{1}{4}x - 2 + 4\\\\y = \frac{1}{4}x + 2[/tex]

Therefore, the slope-intercept form of the equation of the line that passes through (8, 4) and (0, 2) is: [tex]y = \frac{1}{4}x + 2[/tex]

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