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A balanced equation for combustion of methane is given below:
CH
4
(
g
)+2O
2
(
g
)→CO
2
(
g
)+2H
2
O(
g
)
Which of the following statements is not correct on the basis of the above chemical equation?
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Solution
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Correct option is
C
22.4 L methane reacts with 44.8L of oxygen to give 44.8L of CO
2
and 22.4 L of water
CH
4
(g)+2O
2
(g)→CO
2
(g)+2H
2
O(g)
Since 1 mole methane = 12+4×1=16 g and 2 mole oxygen =2×32=64 g, 1 mole CO
2
=12+32=44 g and 2 mole water=2×18=36 g
From the balanced reaction: One mole(or 1 molecule or 16 g) of CH
4
reacts with 2 moles (or 2 molecules or 64 g) of oxygen to give one mole (or 1 molecule or 44 g) of CO
2
and 2 mole (or 2 molecules or 36 g) of water.
For the gaseous system at STP:
22.4 L methane reacts with 44.8 L of oxygen to give 22.4 L of CO
2
and 44.8 L of water.
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Solution to Question ID 924553
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