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Sagot :
The equation in slope-intercept form of the line passing through the given points is: C. [tex]y = \frac{9}{13}x + 7[/tex]
Given the following points:
- Points on the x-axis = (-26, 39)
- Points on the y-axis = (-11, 34)
To find the equation in slope-intercept form of the line passing through the given points:
Mathematically, the equation of slope is calculated by using this:
[tex]Slope. \;m = \frac{Change \; in \; y \;axis}{Change \; in \; x \;axis} \\\\Slope. \;m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
Substituting the given points, we have:
[tex]Slope. \;m = \frac{34 - [-11]}{39 - (-26)}\\\\Slope. \;m = \frac{34\; + \;11}{39 \;+ \; 26}\\\\Slope. \;m = \frac{45}{65}\\\\Slope. \;m = \frac{9}{13}[/tex]
The standard form of an equation of line is given by the formula;
[tex]y = mx + b[/tex]
Where:
- x and y are the points.
- m is the slope.
- b is the intercept.
We would find the intercept:
[tex]-11 = \frac{9}{13}(-26) + b\\\\ -11 = -18 + b\\\\b = -11 + 18[/tex]
Intercept, b = 7
The equation in slope-intercept form of the line is:
[tex]y = \frac{9}{13}x + 7[/tex]
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