The required code written in python 3 which is a function named my_sqrt, which takes in one argument and returns the estimated square root value of the argument inputted.
def my_sqrt(a):
# initiates a function named , my_sqrt
x = 1
# assigns a starting value of 1 to the variable named x
while True:
# initiates a while loop
y = (x + a / x) / 2.0
#calculates the value of y until y equals to x
if y == x:
break
#once, the value of y equals to 1 ; break out of the loop
x = y
#assign the value of y to x
return y
# return y
a = 25
print(my_sqrt(a))
Testing the function with an argument of a = 25 ; the output is attached in the picture below.
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