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Sagot :
There are several ways two triangles can be congruent.
- [tex]\mathbf{AC = BD}[/tex] congruent by SAS
- [tex]\mathbf{\angle ABC \cong \angle BAD}[/tex] congruent by corresponding theorem
In [tex]\mathbf{\triangle AOL}[/tex] and [tex]\mathbf{\triangle BOK}[/tex] (see attachment), we have the following observations
[tex]1.\ \mathbf{AO = DO}[/tex] --- Because O is the midpoint of line segment AD
[tex]2.\ \mathbf{BO = CO}[/tex] --- Because O is the midpoint of line segment BC
[tex]3.\ \mathbf{\angle AOB =\angle COD}[/tex] ---- Because vertical angles are congruent
[tex]4.\ \mathbf{\angle AOC =\angle BOD}[/tex] ---- Because vertical angles are congruent
Using the SAS (side-angle-side) postulate, we have:
[tex]\mathbf{AC = BD}[/tex]
Using corresponding theorem,
[tex]\mathbf{\angle ABC \cong \angle BAD}[/tex] ---- i.e. both triangles are congruent
The above congruence equation is true because:
- 2 sides of both triangles are congruent
- 1 angle each of both triangles is equal
- Corresponding angles are equal
See attachment
Read more about congruence triangles at:
https://brainly.com/question/20517835
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