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A bag of mixed nuts has 12 almonds, 14 cashews, and 18 peanuts. If one nut is removed, what is the probability that an
almond is selected?
Provide the answer as a simplified fraction.
Provide your answer below:
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Sagot :

Probability can be defined as the certainty or the possibility that an event will occur.

The probability that an almond was selected if one nut is removed is 3/11

From the question,

Number of almonds  = 12

Number of cashews = 14

Number of peanuts = 18

Total number of mixed nuts = 12 + 14 + 18

= 44 mixed nuts

The probability that an almond was selected if one nut is removed is calculated as:

P ( Almonds) = Number of almonds/ Total number of mixed nuts

= 12/44

As a simplified fraction:

= 3/11

Therefore, the probability that an almond is selected is 3/11

https://brainly.com/question/9481748

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