IDNLearn.com provides a collaborative environment for finding and sharing answers. Get step-by-step guidance for all your technical questions from our knowledgeable community members.
The energy stored in the spring is 2.25 J.
Given that the energy stored in a spiral spring is E = 1/2 k e^2
Where;
E = energy stored in the spring
k = force constant
e = extension
We can obtain the force constant as the slope of the graph;
k = 25 - 5/0.5 - 0.1
k = 20/0.4
k = 50 N/m
Substituting into the equation when e = 0.3,
E = 1/2 × 50 × (0.30)^2
E = 2.25 J
Learn more: https://brainly.com/question/10991960