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Calculate the wavelength associated with electrons moving with p.d of 1500v

Sagot :

Answer:

3.16X10∧-11 m

Explanation:

1/2 mv2 = qV (KE = Electric potential energy)

velocity = √2qV/m = √( 2X 1.6X10∧-19 X 1500/9.11X10∧-31)

2.3X10∧7m/s

now use De Broglie equation

λ = h/mv

= 6.62X10∧-34/( 9.11X10∧-31 X 2.3X10∧7)

3.16 X 10∧-11 m

or

use the above equations and substitute to get the final eqiation

λ = h/√(2mqV) = 3.16X 10∧-11 m

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