Find expert answers and community insights on IDNLearn.com. Our community is here to provide the comprehensive and accurate answers you need to make informed decisions.
In the first 7.00 seconds, the car travels a distance of
1/2 (1.20 m/s²) (7.00 s)² = 29.4 m
and after this time it will have reached a speed of
(1.20 m/s²) (7.00 s) = 8.40 m/s
Afterwards, the car slows to a stop under uniform acceleration, so that
0² - (8.40 m/s)² = 2 (-4.25 m/s²) x
where x is the distance traveled in the time it takes for the vehicle to stop. Solve for x :
x = (8.40 m/s)² / (2 (4.25 m/s²)) ≈ 8.30 m
So, the total distance traveled is approximately 29.4 m + 8.30 m ≈ 37.7 m.