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In the first 7.00 seconds, the car travels a distance of
1/2 (1.20 m/s²) (7.00 s)² = 29.4 m
and after this time it will have reached a speed of
(1.20 m/s²) (7.00 s) = 8.40 m/s
Afterwards, the car slows to a stop under uniform acceleration, so that
0² - (8.40 m/s)² = 2 (-4.25 m/s²) x
where x is the distance traveled in the time it takes for the vehicle to stop. Solve for x :
x = (8.40 m/s)² / (2 (4.25 m/s²)) ≈ 8.30 m
So, the total distance traveled is approximately 29.4 m + 8.30 m ≈ 37.7 m.