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My teacher didn’t explain how to do these sort of problems very well, and didn’t even give notes that made sense. If anybody could answer this for me it would be greatly appreciated. I’ve been stuck on this problem for an hour.

My Teacher Didnt Explain How To Do These Sort Of Problems Very Well And Didnt Even Give Notes That Made Sense If Anybody Could Answer This For Me It Would Be G class=

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Answer:

m < SQT = 116°

Step-by-step explanation:

Given that QS bisects < RQT, then it means that <RQS = <SQT

To find the measure of <SQT, we can establish the following equation:

<RQS = <SQT

[4x - 20]° = [3x + 14]°

We can simply solve for x:

4x - 20 = 3x + 14

Subtract 3x from both sides:

4x - 3x - 20 = 3x - 3x + 14

x - 20 = 14

Add 20 to both sides to solve for x:

x - 20 + 20 = 14 + 20

x = 34

Now that we have the value for x, we can substitute x = 34 into the equation to find the measures of <RQS and <SQT:

<RQS = <SQT

[4x - 20]° = [3x + 14]°

[4(34) - 20]° = [3(34) + 14]°

136° - 20° = 102° + 14°

116° = 116°

Therefore, the measure of < SQT is 116°

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