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The kinetic energy of ball 1 is given by the equation: equation image indicator and the kinetic energy of ball 2 is given by the table below. Which ball has a higher kinetic energy at v= 2 if we assume m = 1?

Sagot :

Kinetic energy is the energy of a body, when in motion.

The kinetic energy of ball 1 is greater than the kinetic energy of ball 2.

The question is incomplete, as the table is not given; so, I will give a general explanation.

The kinetic energy of a body is:

[tex]\mathbf{KE = \frac 12mv^2}[/tex]

Where:

[tex]\mathbf{v \to velocity}[/tex]

[tex]\mathbf{m \to mass}[/tex]

Assume, the following parameters for ball 1

[tex]\mathbf{m= 1kg}[/tex]

[tex]\mathbf{v= 2ms^{-1}}[/tex]

So, the kinetic energy of ball 1 is:

[tex]\mathbf{KE = \frac 12 \times 1 \times 2^2}[/tex]

[tex]\mathbf{KE = \frac 12 \times 1 \times 4}[/tex]

[tex]\mathbf{KE = 2J}[/tex]

Assume, the following parameters for ball 2

[tex]\mathbf{m= 2kg}[/tex]

[tex]\mathbf{v= 1ms^{-1}}[/tex]

So, the kinetic energy of ball 2 is:

[tex]\mathbf{KE = \frac 12 \times 2 \times 1^2}[/tex]

[tex]\mathbf{KE = \frac 12 \times 2 \times 1}[/tex]

[tex]\mathbf{KE = 1J}[/tex]

Using the assumed parameters, we can conclude that ball 1 has a higher kinetic energy than ball 2.

Read more about kinetic energy at:

https://brainly.com/question/12669551