DayjaRutherford101idn
Answered

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Given R=0.0821L⋅atm / mol⋅K, what is the volume of mole of gas at a pressure of 3.12 atm and a temperature of 270K?
A. 69.2 L/mol

B. 7.10 L/mol

C. 86.5 L/mol

D. 22.2 L/mol

Sagot :

MeMeMeMemMmemrnidn

Answer: the answer is 7.10, B

Step-by-step explanation:

Basically you multiply 0.0821 and the temperature 270K together to get 22.167. Then you divide that by the atm of 3.12 to get 7.10.

(if it helps I also took the test and that was the correct answer.)

Mc1157tidn

Answer:

7.10 L/mol

Step-by-step explanation:

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