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A company surveyed 2,600 North American airline passengers and reported that approximately 75% said that they carry a smartphone when they travel. Suppose that the actual percentage is 75%. Consider randomly selecting six passengers and define the random variable x to be the number of the six selected passengers who travel with a smartphone. The probability distribution of x is the binomial distribution with n

Sagot :

The probability that exactly six out of ten carry a smartphone when travelling is; P(6) = 0.146

The missing part of the question is;

The probability distribution of x is the binomial distribution with n = 10 and p = 0.75.

Calculate P(6)

  • This is a binomial probability distribution problem that has a general formula as; P(x) = ⁿCₓ × pˣ × q⁽ⁿ ⁻ ˣ⁾

Where;

p is probability of success

q is probability of failure

n is number of experiments

In this question;

n = 10

p = 75% = 0.75

q = 1 - p

q = 1 - 0.75

q = 0.25

Since six passengers are randomly selected, then applying the formula earlier quoted, we have;

P(6) = ¹⁰C₆ × 0.75⁶ × 0.25⁽¹⁰ ⁻ ⁶⁾

P(6) = 0.146

Read more at; https://brainly.com/question/24239758

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