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If f(x)=(x^2 - 3)^4, then f'(1) = ?

Sagot :

Answer:

f(1) = 16

Step-by-step explanation:

Substitute x = 1 into f(x) , that is

f(1) = [tex](1^2-3)^{4}[/tex]

     = [tex](1-3)^{4}[/tex]

     = [tex]-2)^{4}[/tex]

    = 16

UserIndonesiaidn

Answer:

16

Step-by-step explanation:

f(x) = (x² - 3)⁴

f(1) = (1² - 3)⁴

f(1) = (-2)⁴

f(1) = (-2 × (-2) × (-2) × (-2))

f(1) = (-4 × (-2) × (-2))

f(1) = (-8 × (-2))

f(1) = 16

Conclusion:

If f(x) = (x² - 3)⁴ then f(1) is 16.

[tex] [/tex]

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