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Sagot :
Answer:
.54 mol
Explanation:
Using the ΔH given for the balanced reaction, convert kilojoules to moles of CO2 using the stoichiometric ratio:
250 kJ×(6 moles CO22803 kJ)=0.5351 moles CO2
The answer should have two significant figures, so round to 0.54 moles CO2.
Notice that coefficients in stoichiometric equations (indicating numbers of moles) are exact, so they do not constrain the number of significant figures.
0.54 moles of carbon dioxide produces 250 kJ.
The equation of the reaction is; 6CO2 + 6H2O → C6H12O6 + 6O2
We can see from the reaction that;
6 moles CO2 produces 2803 kJ
x moles of CO2 produces 250 kJ
x = 6 moles × 250 kJ/2803 kJ
x = 0.54 moles
This means that 0.54 moles of carbon dioxide produces 250 kJ.
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Missing parts;
If 250 kJ of energy are absorbed in the following reaction, how many moles of CO2 reacted:
6CO2 + 6H2O → C6H12O6 + 6O2 ΔH=2803 kJ
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