Answered

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how many aluminum atoms are there in 3.50 grams of al2o3?

Sagot :

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Answer:

4.13×10^22 atoms

Explanation:

1. Find number of moles

mole=mass/rmm of compound

mole= 3.50/102

mole= 7/204 mol

2. Multiply it with avagadros constant( 6.02×10^23 particles)

7/204 × 6.02×10^23= 2.0657×10^22

3. Multiply it with the number of ALMINIUM ATOMS IN AL203( which is 2 atoms)

2.0657×10^22 × 2

you get 4.13×10^22 atoms

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