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Mrs. Johnson put 22,250 miles
on her car in 2011 and 14,500
miles in 2012. Find the percent
decrease in miles driven
from 2011 to 2012.

help.


Sagot :

The change in quantities can be represented as percentage

The percentage decrease in miles driven is 34.83%

The given parameters are:

[tex]\mathbf{Initial = 22250}[/tex]

[tex]\mathbf{Final = 14500}[/tex]

The percentage decrease is calculated as:

[tex]\mathbf{\%Decrease = \frac{Final - Initial}{Initial} \times 100\%}[/tex]

Substitute known values

[tex]\mathbf{\%Decrease = \frac{14500- 22250}{22250} \times 100\%}[/tex]

[tex]\mathbf{\%Decrease = \frac{-7750}{22250} \times 100\%}[/tex]

[tex]\mathbf{\%Decrease = \frac{-775000}{22250} \%}[/tex]

[tex]\mathbf{\%Decrease = -34.83 \%}[/tex]

The negative sign implies that, the change represents a decrement.

Hence, the percentage decrease in miles driven is 34.83%

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