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What is the pressure of the sample of gas trapped in the open-tube mercury manometer shown below if atmospheri pressure is 767 mmHg and h = 8.9 cm Hg?

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Here, we are required to determine the pressure of the sample of gas trapped in the open-tube mercury manometer shown below if Atmospheric pressure is 767 mmHg and pressure head, h = 8.9 cmHg.

  • The pressure of the sample of gas trapped in the open-tube mercury manometer is;. 856 mmHg

According to the question;

  • The atmospheric pressure is 767 mmHg

  • The gauge pressure is 8.9 cmHg = 89mmHg.

The absolute pressure, P(abs);

is given mathematically as;

Absolute pressure = Atmospheric pressure + gauge pressure.

P(abs) = P(atm) + P(gauge)

P(abs) = 767mmHg + 89mmHg.

P(abs) = 856 mmHg.

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