Kamrynhardythemusiclidn
Answered

IDNLearn.com provides a comprehensive solution for all your question and answer needs. Ask any question and get a thorough, accurate answer from our community of experienced professionals.

A two-digit locker combination has two nonzero digits and no two digits are the same. Event A is defined as choosing an odd digit for the first number, and event B is defined as choosing an even digit for the second number. If a combination is picked at random, with each possible locker
combination being equally likely, what is P(B|A) expressed in simplest
form?

A) 1/9
B) 1/8
C)1/2
D) 5/9

Sagot :

Answer:

Event A = 5/9

Event B = 4/8

we multiply these to get 5/9 x 4/8 = 20/72 = EVEN ODD

and 4/9 x 4/8  = 16/72  ODD EVEN

5/9 X 5/ 8 = 25/72 =  ODD ODD

4/9 X 3/8 = 12/72 = EVEN EVEN

Therefore; Random =

P) (20 + 16 + 25 + 12) / 4(72) = 72/ 4(72) =72/ 288 = 0.25 = 1/4

Step-by-step explanation:

Answer:

MY name's Jeff and The answer's 5/9

Step-by-step explanation:

The amount of odd numbers are 5 and out of the 9 you have a chance of getting one, so you would have a 5/9 chance

Tell me if I'm incorrect

We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Discover the answers you need at IDNLearn.com. Thank you for visiting, and we hope to see you again for more solutions.