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Sagot :
Velocity is a vector quantity, given by magnitude and direction. The initial vertically downward velocity of an object moving horizontally, is zero
a) The time it takes the bullet to strike the ground, is approximately 0.856 s
b) The horizontal distance travelled by the bullet is approximately 865 meters
Reason:
Known parameter;
Height of the riffle above ground, h = 4.20 m
Initial speed of the bullet, vₓ = 1010 m/s
a) The time, t, it takes the bullet to strike the ground, is given by the relation;
[tex]t = \sqrt{\dfrac{2 \cdot h}{g} }[/tex]
Where;
g = Acceleration due to gravity ≈ 9.81 m/s²
- [tex]\therefore t = \sqrt{\dfrac{2 \times 4.20}{9.81} } \approx 0.856[/tex]
The time it takes the bullet to strike the ground, t ≈ 0.856 s
b) The horizontal distance travelled by the bullet, d = vₓ×t
Where;
t = Time of flight = Time it takes the bullet to hit the ground ≈ 0.856 s
Therefore, rounding to 3 significant figures, we have;
- d ≈ 1010 m/s × 0.856 s ≈ 865 m
The horizontal distance travelled by the bullet, d ≈ 865 m
Learn more about the trajectory of falling objects here:
https://brainly.com/question/24705289
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