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[ 1 / √3 - 1 ] + [ 1 / √3 + 1 ] =
[ ( √3 + 1 / √3 + 1 )( 1 / √3 - 1 ) ] +
[ ( √3 - 1 / √3 - 1 )( 1 / √3 + 1 ) ] =
[ √3 + 1 / ( √3 + 1 )( √3 - 1 ) ] +
[ √3 - 1 / ( √3 + 1 )( √3 - 1 ) ] =
√3 + 1 + √3 - 1 / ( √3 + 1 )( √3 - 1 ) =
2√3 / ( √3 )^2 - ( 1 )^2 =
2√3 / 3 - 1 =
2√3 / 2 =
2 × √3 / 2 × 1 =