Answered

Join IDNLearn.com and start exploring the answers to your most pressing questions. Our platform offers comprehensive and accurate responses to help you make informed decisions on any topic.

need an answer, please need an answer, please​

Need An Answer Please Need An Answer Please class=

Sagot :

Devishri1977idn

Answer:

Step-by-step explanation:

Quadratic equation: ax² +bx + c = 0

D = b² - 4ac

1) 4x² - 3x - 2 = 0

a = 4  ; b = -3  ; c = -2

D = (-3)² - 4*4*(-2)

   = 9  + 32

    = 41

D > 0, So, two distinct real roots.

2) 5x² + 2x - 3 = 0

a = 5 ; b = 2 ; c = -3

D = 2² - 4*5*(-3)

 = 4 + 60

 = 64

D >0 . So, two distinct real roots.

3)9x² - 6x + 1 = 0

a = 9 ; b = -6 ;c =1

D = (-6)² - 4*9*1

  = 36 - 36

  = 0

D = 0.  So, two equal real roots.

4)3x² + 7x + 8 = 0

a = 3 ; b = 7 ; c = 8

D = 7² - 4*3*8

   = 49 - 96

  = - 47

D < 0 .So, two roots are complex and different.

5) 8x² + 5x = 0

a = 8 ; b = 5 ;  c = 0

D = 5² - 4*8*0

  = 25 - 0

 = 25

D > 0. So, two distinct real roots.

Djtwinx017idn

Answer:

Attached are the solutions to the given table.

One thing to remember about Quadratic Formula and Discriminants:

  • if b² - 4ac = 0, then the equation has one real root.
  • if b² - 4ac > 0, then the equation have two real roots.
  • if b² - 4ac < 0, then the equation  have two complex roots.
View image Djtwinx017
Your participation is crucial to us. Keep sharing your knowledge and experiences. Let's create a learning environment that is both enjoyable and beneficial. Your questions deserve reliable answers. Thanks for visiting IDNLearn.com, and see you again soon for more helpful information.