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Sagot :
The final pressure in the container if the temperature remains constant is 68.3 kPa.
Given the following data;
- Initial volume, V1 = 4.0 liters
- Initial pressure, P1 = 205 kPa
- Final volume, V2 = 12.0 Liters
To find the final pressure in the container if the temperature remains constant, we would use Boyle's Law:
Mathematically, Boyle's law is given by the formula;
[tex]P_1V_1 = P_2V_2[/tex]
Where;
- P1 is the original (initial) pressure.
- P2 is the final pressure.
- V1 is the original (initial) volume.
- V2 is the final volume.
Substituting the values into the formula, we have;
[tex]205[/tex] × [tex]4 =[/tex] [tex]12P_2[/tex]
[tex]820 = 12P_2\\\\P_2 = \frac{820}{12}[/tex]
Final pressure, P2 = 68.3 kPa
Therefore, the final pressure in the container if the temperature remains constant is 68.3 kPa.
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