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(w2x−3)÷10⋅z when w=−9, x = 2.7, and z=−2/5

Sagot :

  • w=-9
  • x=2.7
  • z=-2/5

[tex]\\ \sf\longmapsto \dfrac{w^2x-3}{10z}[/tex]

[tex]\\ \sf\longmapsto \dfrac{(-9)^2(2.7)-3}{10(-2/5)}[/tex]

[tex]\\ \sf\longmapsto \dfrac{81(2.7)-3}{-2(2)}[/tex]

[tex]\\ \sf\longmapsto \dfrac{218.7-3}{-4}[/tex]

[tex]\\ \sf\longmapsto \dfrac{215.7}{-4}[/tex]

  • Rounding up numerator

[tex]\\ \sf\longmapsto \dfrac{216}{-4}[/tex]

[tex]\\ \sf\longmapsto -44[/tex]

Bora77idn

Step-by-step explanation:

(-9)^2(2.7)-3/10(-2/5

= 81(2.7)-3/-2(2)

= 218.7-3/-4

= 215.7/-4

= -44

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