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Sagot :
Answer:
The function of this equation is: [tex]F(n)=\frac{1}{4}n^4-\frac{1}{3}n^3+n+C[/tex]
Step-by-step explanation:
Answer:
1, 5, 19, 49
Step-by-step explanation:
To obtain the first 4 terms substitute n = 1, 2, 3, 4 into f(n)
f(1) = 1³ - 1² + 1 = 1 - 1 + 1 = 1
f(2) = 2³ - 2² + 1 = 8 - 4 + 1 = 4 + 1 = 5
f(3) = 3³ - 3² + 1 = 27 - 9 + 1 = 18 + 1 = 19
f(4) = 4³ - 4² + 1 = 64 - 16 + 1 = 48 + 1 = 49
The first 4 terms are 1, 5, 19, 49
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