IDNLearn.com: Where questions are met with accurate and insightful answers. Discover prompt and accurate responses from our experts, ensuring you get the information you need quickly.
Sagot :
It will take the quarter 0.151 seconds to reach the ground.
Given the following data:
- Height = 1.45 meters
- Initial velocity = 10.32 m/s
We know that acceleration due to gravity (a) for an object is equal to 9.8 meter per seconds square.
To find how much time it will take the quarter to reach the ground, we would use the second equation of motion.
Mathematically, the second equation of motion is given by the formula;
[tex]S = ut + \frac{1}{2} at^2[/tex]
Where:
- S is the height or distance covered.
- u is the initial velocity.
- a is the acceleration.
- t is the time measured in seconds.
Substituting the values into the formula, we have;
[tex]1.45 = 10.32(t) + \frac{1}{2} (9.8)t^2\\\\1.45 = 10.32t + 4.9t^2\\\\4.9t^2 + 10.32t - 1.45 = 0[/tex]
The standard form of a quadratic equation is:
[tex]ax^2 + bx + c = 0[/tex]
a = 4.9, b = 10.32 and c = 1.45
We would solve the above quadratic equation by using the quadratic equation formula;
[tex]x = \frac{-b\; \pm \;\sqrt{b^2 - 4ac}}{2a}[/tex]
Substituting the values, we have;
[tex]t = \frac{-10.32\; \pm \;\sqrt{10.32^2\; - \;4(4.9)(1.45)}}{2(4.9)}\\\\t = \frac{-10.32\; \pm \;\sqrt{106.5024\; - \;28.42}}{9.8}\\\\t = \frac{-10.32\; \pm \;\sqrt{78.0824}}{9.8}\\\\t = \frac{-10.32\; \pm \;8.84}{9.8}\\\\t = \frac{-10.32\; + \;8.84}{9.8}\\\\t = \frac{1.48}{9.8}[/tex]
Time, t = 0.151 seconds.
Therefore, it will take the quarter 0.151 seconds to reach the ground.
Read more: https://brainly.com/question/8898885
We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. IDNLearn.com is your reliable source for accurate answers. Thank you for visiting, and we hope to assist you again.