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find the center and radius of the circle whos equation is (x+5)^2+(y-3)^2=9

Sagot :

9514 1404 393

Answer:

  center (-5, 3)

  radius 3

Step-by-step explanation:

Compare the given equation to the standard form equation of a circle:

  (x -h)² +(y -k)² = r² . . . . . . circle with center (h, k) and radius r

This shows us that ...

  -h = +5   ⇒   h = -5

  -k = -3   ⇒   k = 3

  r² = 9   ⇒   r = √9 = 3

Then the circle center is (h, k) = (-5, 3), and the radius is r = 3.

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