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7. Write the equation of a line which passes through the points (-3,5) and (6,23)

Sagot :

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Answer:

answer to the equation is

[tex]y = 2x + 11[/tex]

Step-by-step explanation:

[tex]y = mx + b[/tex]

first find the slope of the line using the two points

[tex]slope \: m = \frac{y2 - y1}{x2 - x1} = \frac{23 - 5}{6 - ( - 3)} \\ = \frac{18}{9} \\ slope \: m = 2[/tex]

substitute 2 for m and use one of the points for x and y and solve for b

[tex]5 = 2( - 3) + b \\ 5 = - 6 + b \\ 5 + 6 = b \\ b = 11[/tex]

Now that you found b, the y-intercept, you can substitute that into the equation for your line

[tex]y = 2x + 11[/tex]

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