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[tex]3x-5y=11 \\
x=3y+1 \\ \\
\hbox{substitute 3y+1 for x in the 1st equation and solve for y:} \\
3(3y+1)-5y=11 \\
9y+3-5y=11 \\
4y+3=11 \\
4y=11-3 \\
4y=8 \\
y=\frac{8}{4} \\
y=2 \\ \\
\hbox{now substitute 2 for y in one of the equations and solve for x:} \\
x=3 \times 2 +1 \\
x=6+1 \\
x=7 \\ \\
\hbox{the answer:} \\
x=7 \\ y=2[/tex]
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