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The theater sells two types of tickets: adult tickets for $14 and child tickets for $8.
Last night, the theater sold a total of 159 tickets for a total of $1794. How many adult tickets did the theater sell last night?

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Answer:

87 Adult tickets were sold

Step-by-step explanation:

This type of question relates to a system of equations. These types of questions are pretty easy to spot and they are just about solved all the same way.

So what we first want to do is see that there is a total of 159 tickets sold. Now obviously that number consists of the adult and children tickets, therefore we need to add those two unknown numbers to get 159, so x will be for adults and y will be for children tickets. this will give us the equation x + y= 159.

Next, we want to associate the amount those tickets are with those variables, because you can only have so many adult tickets and children tickets with the given $1794. So what we need to do is similar, we just have those totals added to get the equation 14x + 8y = 1794.

Now we want to use the process of elimination to find the value of x (because we are solving how many adult tickets were sold). IN order to do elimination, we need to have the equation x + y= 159 cancel the y value to leave us with the x value. In order to do this, you need to multiply y by a value that cancels 8y in 14x + 8y = 1794, which is -8.

So we multiply the entire equation of x + y= 159 by -8 to get. Now we would add these equations together where you subtract by like terms so:

[tex]14x + 8y = 1794\\-8x - 8y = -1272[/tex]

This leaves us with 6x=522 now you would divide by 6 to isolate x which leaves you with 87.

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