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This equation tells the position of the ball, x, at any time t. Let's use it to solve for the position of the ball at t=0.00231 s. What value do you get when you use t=0.00231 s and solve for the position, x?

Sagot :

The slope of the graph, A, and the starting position of the ball, B, can be used to determine the position of the ball

  • The position of the ball at time t = 0.00231 s is 59.933 cm

Reason:

Question; The possible function representing the given equation is presented as follows;

x = A·t + B

Where;

A = 2.59 × 10⁴ [tex]\frac{cm}{s}[/tex]

B = 0.104 cm

t = Time in seconds (s)

x = The position (cm)

Required: The value of the position when t = 0.00231 s

Solution:

The position time graph of an object moving with a constant speed is a straight line with an equation of the form y = m·x + c

Plugging in the value of t = 0.00231 in the given equation gives;

x = 2.59 × 10⁴ × 0.00231 + 0.104 = 59.933

The position x of the ball at time, t = 0.00231 s is 59.933 cm

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