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We have to find b
[tex]\\ \sf\longmapsto y=mx+b[/tex]
[tex]\\ \sf\longmapsto -1=\dfrac{-2}{3}(-3)+b[/tex]
[tex]\\ \sf\longmapsto -1=-2(-1)+b[/tex]
[tex]\\ \sf\longmapsto -1=2+b[/tex]
[tex]\\ \sf\longmapsto b=-3[/tex]
Now put in equation
[tex]\\ \sf\longmapsto y=\dfrac{-2}{3}x-3[/tex]
Option D