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In ΔQRS, q = 9.4 cm, r = 8 cm and ∠S=151°. Find ∠Q, to the nearest 10th of a degree.

Sagot :

Sqdancefanidn

9514 1404 393

Answer:

  15.7°

Step-by-step explanation:

The law of cosines can be used to find side s:

  s² = r² +q² -2rq·cos(S)

  s² = 8² +9.4² -2(8)(9.4)·cos(151°) ≈ 283.903

  s ≈ 16.849

Then the law of sines can be used to find angle Q.

  sin(Q)/q = sin(S)/s

  sin(Q) = (q/s)sin(S)

  Q = arcsin(q/s·sin(S)) = arcsin(9.4/16.849·sin(151°)) ≈ 15.692°

Angle Q is about 15.7°.

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