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Solve for d.

3 + d ≤ 3 - d

Sagot :

Spammingallowedidn

Answer:

[tex]3 + d \leqslant 3 - d \\ d + d \leqslant 3 - 3 \\ 2d \leqslant 0 \\ d \leqslant 0 \\ thank \: you[/tex]

Darkness880826idn

1) Cancel 3 on both sides

d≤−d

2) Subtract -d from both sides.

d+d≤0

3) Simplify  d+d  to  2d.

2d≤0

4)  Divide both sides by 2.  

d≤0

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