Gpaudel826idn
Answered

Get expert insights and community-driven knowledge on IDNLearn.com. Discover detailed answers to your questions with our extensive database of expert knowledge.

cos^8a+sin^8a=1-sin^22a+1/8sin^4a​

Sagot :

Darkness880826idn

cos⁸A+sin⁸A = (Cos⁴A)² + (Sin⁴A)²

=> (Cos⁴A + Sin⁴A)² - 2Cos⁴ASin⁴A

=> [(Cos²A)²+(Sin²A)²]² - 2(CosASinA)⁴

=> [(Cos²A+Sin²A)² - 2Cos²ASin²A]² - 2(CosASinA)⁴

=> [1 - 2Cos²ASin²A]² - 2(CosASinA)⁴

=> [1 - 2(CosASinA)²]² - 2(CosASinA)⁴

//Remember: Sin2A = 2SinA CosA => SinACosA = 1/2Sin2A

=> [1 - 2(1/2Sin2A)²]²- 2(1/2Sin2A)⁴

=> [1 - 1/2Sin²2A]² - 1/8Sin⁴2A

=> 1 + 1/4Sin⁴2A - Sin²2A - 1/8Sin⁴2A

=> 1 - Sin²2A + 1/8Sin⁴2A

=> R.H.S

Thank you for contributing to our discussion. Don't forget to check back for new answers. Keep asking, answering, and sharing useful information. Thank you for choosing IDNLearn.com. We’re dedicated to providing clear answers, so visit us again for more solutions.