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The length of a rectangle is 7 feet less than three times the width, and the area of the rectangle is 66ft^2 . Find the dimensions of the rectangle.

Sagot :

Answer:

Step-by-step explanation:

w = width

3w = three times the width

3w-7=7 feet less than three times the width

l = length = 3w-7

A=length × width (lw)

66 = (3w-7) × (w)

66 = 3w^2 - 7w

3w^2 - 7w -66 =0

factor

3 = 3 × 1 and 66 = 6 × 11,

6 × 3 = 18,  11 × 1 = 11,  18 - 11 = 7

(3w   )(w   )=0 so far

(3w   )(w  6)=0 so far

(3w   11)(w   6)=0 so far

(3w+11)(w-6)=0

w-6=0

w=6

3w=3*6=18

3w-7=3*6-7=18-7=11

w=6 feet

l=11 feet