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Answer:
x= plus or minus square root of 19 -4
Step-by-step explanation:
x^2+8x ___=3
take half of your b term (8) and then multiply by two and add or subtract it to both sides
x^2+8x+16=3+16
then combine like terms
x^2+8x+16=19
then factor your quadratic equation
(x+4)^2=19
now solve for x
take the square root of (x+4)^2 to get rid of the ^2
you then also have to square the 19 because what you do to one side you have to do to the other
(x+4)= square root of 19
subtract 4 from both sides
x= plus or minus square root of 19 -4
Answer:
Step-by-step explanation:
Divide the coefficient of x by 2
8/2 = 4. Now find the square of 4 = 4² = 16
Add 16 to both sides of the equation
x² + 8x + 16 = 3 + 16
x² + 2* x * 4 + 4² = 19
{Compare with a² + 2ab + b² = (a + b)² }
(x + 4)² = 19
Both sides take square root,
[tex]\sqrt{(x+ 4)^{2}}=\sqrt{19}\\\\x + 4 = \sqrt{19}[/tex]
x + 4 = ± 4.36
x + 4 = 4.36 ; x + 4 = -4.36
x = 4.36 -4 ; x = -4.36 - 4
x = 0.36 ; x = - 8.36