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Sagot :

  • Length=L=40m
  • Breadth=B=30m

Perimeter:-

[tex]\\ \sf\longmapsto 2(L+B)[/tex]

[tex]\\ \sf\longmapsto 2(40+30)[/tex]

[tex]\\ \sf\longmapsto 2(70)[/tex]

[tex]\\ \sf\longmapsto 140m[/tex]

Area

[tex]\\ \sf\longmapsto LB[/tex]

[tex]\\ \sf\longmapsto 40(30)[/tex]

[tex]\\ \sf\longmapsto 1200m^2[/tex]

Length (L) of Rectangle = 40 m

Breadth (B) of Rectangle = 30m

Perimeter of Rectangle:-

= 2(Length + Breadth)

= 2(40 + 30)

= 2(70)

= 140m

Area of Rectangle:-

= Length × Breadth

= 40 × 30

= 1200m^2

Therefore, The perimeter of the rectangle is 140m and the area of the rectangle is 1200m^2.

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