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Sagot :
Answer:
122.5 meters
Explanation:
We have the third equation of motion:
[tex]\boxed{\mathsf{v^2=u^2+2aS}}[/tex]
- v stands for the final velocity
- u, initial velocity
- a is the acceleration of the particle in motion
- S, the distance covered by the same particle.
Here, the particle is a flare.
It's initial velocity is 49 m/ s and the final will be zero, that's 'cause the particle comes to a standstill upon reaching its maximum, in case of motion under gravity.
a will be the acceleration due to gravity = 9.8 m/ s²
So, here are the terms we've got for the third eqn. of motion:
- v = 0 m/ s
- u = 49m/ s
- a = - 9.8 m/ s (the force of gravity acts downwards, and that's the direction we say is negative)
Now, the term we've got to find out is the height reached by the flare, i. e., S.
=> v² = u² + 2aS
=> (0)² = (49)² + 2×(-9.8)×S
=> 0 = 49×49 - 2×9.8×S
=> 2×9.8×S = 49×49
[tex]\implies \mathsf{S=\frac{49\times 49}{2\times9.8} }[/tex]
=> S = [tex]\frac{245}{2}[/tex]
=> S = 122.5 meters
And, S is the maximum height the flare covers, so the answer is 122. 5 meters
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