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How much energy is required to take 500g of ice at -40 degrees to water at room temperature (22 degrees Celsius)? Show work pls

Sagot :

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Answer: Given that:

Mass (m) = 20 g = 0.02 Kg,

temperature (T₁) = -10°C = -10+273 = 263 K

temperature (T₂) = 10°C = 10+273 = 283 K

Specific heat of water (Cp) = 4.187 KJ/Kg k

We know that Heat transfer (Q) = m. Cp.( T₂ - T₁)

                                                   = 0.02 × 4.187 × (283-263)

                                                Q = 1.67 KJ

Heat transferred is 1.67 KJ

Explanation:

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