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You roll a six-sided die. Find the probability of each of the following scenarios
(a) Rolling a 6 or a number greater than 3
(b) Rolling a number less than 5 or an even number
(c) Rolling a 4 or an odd number
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(a) P(6 or number > 3) = 0.500 (Round to three decimal places as needed)
(b) P(1 or 2 or 3 or 4 or 6) =
(Round to three decimal places as needed.)

Sagot :

Danielgeyfmanidn

Answer:

a) [tex]1/2[/tex]

b) [tex]5/6[/tex]

c) [tex]2/3[/tex]

Step-by-step explanation:

a)

Rolling a number greater than 3 means you can roll a 4, 5, or 6, which contains rolling a 6. So, the probability is [tex](1+1+1)/6=3/6=\boxed{1/2}[/tex]

b)

Rolling a number less than 5 means you can roll a 1, 2, 3, or 4, but because you could also roll an even number, so you could also roll a 6.

So, the probability is [tex](1+1+1+1+1)/6=\boxed{5/6}[/tex]

c)

Rolling a 4 or an odd number means you can roll a 1, 3, 5, or 4. So, the probability is [tex](1+1+1+1)/6=4/6=\boxed{2/3}[/tex]

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