IDNLearn.com makes it easy to find the right answers to your questions. Find reliable solutions to your questions quickly and accurately with help from our dedicated community of experts.
Sagot :
[tex]a,a+1,a+2,a+3-\ four\ consecutive\ integers\\\\
a+a+1+a+2+a+3=682\\\\
4a+6=682\ \ \ | subtract\ 6\\\\
4a=676\ \ \ | divide\ by\ 4\\\\
a=169\\\\
Number\ are\ 169,170,171,172.[/tex]
Because they're consecutive, it means that the first one is x, the second one is x+1, the third one is x+2 (x+1+1), and the fourth one is x+3. Because we're given that the sum of all of them is 682, just add all of them together:
x+(x+1)+(x+2)+(x+3)=682
x+x+x+x+1+2+3=682
4x+6=682
4x+6-6=682-6
4x=676
x=676/4
x=169
Thus, the consecutive integers are: 169, 170, 171, 172
x+(x+1)+(x+2)+(x+3)=682
x+x+x+x+1+2+3=682
4x+6=682
4x+6-6=682-6
4x=676
x=676/4
x=169
Thus, the consecutive integers are: 169, 170, 171, 172
Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! IDNLearn.com has the solutions to your questions. Thanks for stopping by, and come back for more insightful information.