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The value of ka for weak acid is to 4.0x10^-5 what is degree of dissociation of the acid in aqueous solution of concentration 0.010 mol dm^-3​

Sagot :

p

K

a

=

5.4

pH

=

3.7

Explanation:

p

K

a

is simply  

log

10

(

K

a

)

. It is a constant at any temperature and does not depend on the molarity of the solution.

p

K

a

=

log

10

(

K

a

)

=

log

10

(

4.0

×

10

6

)

=

5.4Explanation:

It is 5.4 I got the answer because of the guy on top
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